11483 – Code Creator UVA Solution

Fabian Calsina Leave a comment

This is an easy problem from uva judge http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=2478

Ad hoc, Output formatting.

How I did it

  • Read the number of lines of the case.
  • Read the strings and save it into a vector. (vec)
  • Print the static header.
  • Traverse vec and parse the data.
  • Print the static footer.

Hints

  • Careful with ‘\\’                ‘\”                ‘\”‘

Input

1
\Y

3

(empty line)

(empty line)

(empty line)

Output

Case 1:
#include<string.h>
#include<stdio.h>
int main()
{
printf(“\\Y\n”);
printf(“\n”);
return 0;
}

Case 2:
#include<string.h>
#include<stdio.h>
int main()
{
printf(“\n”);
printf(“\n”);
printf(“\n”);
return 0;
}

Code

#include <iostream>
#include <cctype>
#include <cstdio>
#include <vector>
using namespace std;
int  caso = 1;
void printHeader()
{
    printf("Case %d:\n", caso++);
    printf("#include<string.h>\n");
    printf("#include<stdio.h>\n");
    printf("int main()\n");
    printf("{\n");
}

void printInput(string str)
{
    printf("printf(\"");
    for(int c=0; c<str.size(); c++)
    {
        if(isalnum(str[c]) || isspace(str[c]))
          printf("%c",str[c]);
        else if(str[c] == '\"')
                printf("\\\"");
        else if(str[c] == '\'')
                printf("\\\'");
        else if(str[c] == '\\')
                printf("\\\\");
    }
    printf("\\n\");\n");
}

void printFooter()
{
    printf("printf(\"\\n\");\n");
    printf("return 0;\n");
    printf("}\n");
}

int main()
{
int lines;
string str;

while(scanf("%d", &lines))
{
    if(!lines)
       break;

    vector<string> vec;
    getline(cin,str);
    for(int a=0; a<lines; a++)
    {
        getline(cin, str);
        vec.push_back(str);
    }
    printHeader();    for(int x=0; x<vec.size(); x++)
        printInput(vec[x]);
    printFooter();
}
return 0;
}

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